[Q40-Q61] Exam Passing Guarantee May 22, 2024 1z0-071 Exam with Accurate Quastions!

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Exam Passing Guarantee May 22, 2024 1z0-071 Exam with Accurate Quastions!

Test Engine to Practice Test for 1z0-071 Valid and Updated Dumps

Oracle 1z0-071 certification exam is a computer-based exam that consists of 73 multiple-choice questions. 1z0-071 exam is 105 minutes long, and candidates must achieve a score of at least 63% to pass. 1z0-071 exam is available in multiple languages, including English, Japanese, and Simplified Chinese.

Q40. You execute the SQL statement:
SQL> CREATE TABLE citizens
(citizen_id CHAR (10) PRIMARY KEY,
last_name VARCHAR2 (50) NOT NULL,
first_name VARCHAR2 (50),
address VARCHAR2 (100),
city VARCHAR2 (30) DEFAULT ‘SEATTLE’ NOT NULL,
CONSTRAINT cnames CHECK (first_name<>last_name) );
What is the outcome?

It fails because the NOT NULL and DEFAULT options cannot be combined for the same column.

It succeeds and CITY can contain only ‘SEATTLE’ or null for all rows.

It fails because the condition for the CANAMES constraint is not valid.

It succeeds and an index is crated for CITIZEN_ID.

Q41. Which two are true about granting object privileges on tables, views, and sequences?

DELETE can be granted on tables, views, and sequences.

REFERENCES can be grantrd only on tables.

INSERT can be granted only on tables and sequences.

SELECT can be granted on tables, views, and sequences.

ALTER can be granted only on tables and sequences.

Q42. View the Exhibit and examine the structure of the PORDUCT_INFORMATION table.
(Choose the best answer.)

PRODUCT_ID column is the primary key.
You create an index using this command:
SQL > CREATE INDEX upper_name_idx
ON product_information(UPPER(product_name));
No other indexes exist on the PRODUCT_INFORMATION table.
Which query would use the UPPER_NAME_IDX index?

SELECT product_id, UPPER(product_name)FROM product_informationWHERE
UPPER(product_name) = ‘LASERPRO’ OR list_price > 1000;

SELECT UPPER(product_name)FROM product_information;

SELECT UPPER(product_name)FROM product_informationWHERE product_id = 2254;

SELECT product_idFROM product_informationWHERE UPPER(product_name) IN (‘LASERPRO’, ‘CABLE’);

Q43. Examine the types and examples of relationship that follow:
1 One-to-one a) teacher to Student
2 One-to-many b) Employees to Manager
3 Many-to-one c) Person to SSN
4 Many-to-many d) Customers to Products
Which option indicates correctly matched relationships?

1-d, 2-b, 3-a, and 4-c

1-c, 2-d, 3-a, and 4-b

1-a, 2-b, 3-c, and 4-d

1-c, 2-a, 3-b, and 4-d

Q44. Which three queries execute successfully?

SELECT (SYSDATE-DATE ‘2019-01-01’) / 1 FROM DUAL;

SELECT 1 / SYSDATE – DATE ‘2019-01-01’ FROM DUAL;

SELECT SYSDATE / DATE ‘2019-01-01’ – 1 FROM DUAL

SELECT SYSDATE – DATE ‘2019-01-01’ – 1 FROM DUAL;

SELECT 1 – SYSDATE- DATE ‘2019-01-01’ FROM DUAL;

SELECT SYSDATE – 1 – DATE’2019-01-01′ EROM DUAL;

Q45. View the Exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID.
You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?

SELECT m.last_name “Manager”, e.last_name “Employee”
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id=100;

SELECT m.last_name “Manager”, e.last_name “Employee”
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.managerjd=100;

SELECT m.last_name “Manager”, e.last_name “Employee”
FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id=100;

SELECT m.last_name “Manager”, e.last_name “Employee”
FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.managerjd=100;

Q46. View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.

You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the view successfully?

CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;

CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)”NO OF ITEMS”FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;

CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)”NO OF ITEMS”FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;

CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)||’NO OF ITEMS’FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_dateWHITH CHECK OPTION;

Q47. Examine the structure of the EMPLOYEES table. (Choose two.)
You must display the maximum and minimum salaries of employees hired 1 year ago.
Which two statements would provide the correct output?

SELECT MIN(Salary) minsal, MAX(salary) maxsalFROM employeesWHERE hire_date
< SYSDATE-365GROUP BY MIN(salary), MAX(salary);

SELECT minsal, maxsalFROM (SELECT MIN(salary) minsal, MAX(salary) maxsal FROM employeesWHERE hire_date < SYSDATE-365)GROUP BY maxsal, minsal;

SELECT minsal, maxsalFROM (SELECT MIN(salary) minsal, MAX(salary) maxsal FROM employeesWHERE hire_date < SYSDATE-365GROUP BY MIN(salary), MAX(salary);

SELECT MIN(Salary), MAX(salary)FROM (SELECT salary FROM employeesWHERE hire_date < SYSDATE-365);

Q48. Which statement is true about the Oracle SQL, DELETEand TRUNCATEstatements?

DELTEand TRUNCATEstatements can have a rollback done to restore data into a table.

DELETEand TRUNCATEstatements remove all indexes for the tables on which they are performed.

DELETE but not TRUNCATEstatement can be used to remove data from selective columns and rows of a table.

DELETEbut not TRUNCATEstatement can be used to selectively remove rows from a table.

Q49. Examine the description of the PROMOTIONS TABLE:
You want to display the unique is promotion costs in each promotion category.
Which two queries can be used?

SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;

SELECT promo_cost, promo_category FROM promotions ORDER BY 1

SELECT promo_category, DISTINCT promo_cost FROM promotiong ORDER BY 2:

select DISTINCT promo_categoryIl ‘has’||promol_cost as COSTS FROM promotions ORDER BY 1:

SELECT DISTINCT promo_cost ||’in’IIDISTINCT promo_category promotions ORDER BY1;

Q50. View the exhibit and examine the structure of the CUSTOMERStable.

Which two tasks would require subqueries or joins to be executed in a single statement?

finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers

finding the average credit limit of male customers residing in ‘Tokyo’or ‘Sydney’

listing of customers who do not have a credit limit and were born before 1980

finding the number of customers, in each city, who’s marital status is ‘married’.

listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city ‘Tokyo’.

Q51. Viev the Exhibit and examine the structure of the PRODUCT INFORMATION and INVENTORIEStables.
You have a requirement from the supplies department to give a list containing PRODUCT _ID,SUPPLIER ID, and QUANTITY_ON HAND for all the products where in QUANTITY ON HAND is lessthan five.
Which two SQL statements can accomplish the task? (Choose two)

SELECT product id, quantity on hand, supplier id
FROM product information
NATURAL JOIN inventories AND quantity .on hand < 5;

SELECT i. product id, i. quantity .on hand, pi. supplier_id
FROM product_information pi JOIN inventories i
ON (pi. product. id=i. product id) AND quantity on hand < 5;

SELECT i. product_id, i. quantity_on hand, pi. supplier id
FROM product information pi JOIN inventories i USING (product id) AND quantity .on hand < 5;

SELECT i.product id, i. quantity on hand, pi. supplier id
FROM product information pi JOIN inventories i
ON (pi.product id=i. product id)WHERE quantity on hand < 5;

Q52. Which two statements are true regarding the WHERE and HAVING clauses in a SELECT statement? (Choose two.)

The WHERE and HAVING clauses can be used in the same statement only if they are applied to different columns in the table.

The aggregate functions and columns used in the HAVING clause must be specified in the SELECT list of the query.

The WHERE clause can be used to exclude rows after dividing them into groups.

The HAVING clause can be used with aggregate functions in subqueries.

The WHERE clause can be used to exclude rows before dividing them into groups.

Q53. Examine the data in the CUSTOMERStable:

You want to list all cities that have more than one customer along with the customer details.
Evaluate the following query:

Which two JOIN options can be used in the blank in the above query to give the correct output? (Choose two.)

LEFT OUTER JOIN

JOIN

NATURAL JOIN

RIGHT OUTER JOIN

FULL OUTER JOIN

Q54. Which three are true about dropping columns from a table?

A column can be removed only if it contains no data.

A column drop is implicitly committed

A column that is referenced by another column in any other table cannot be dropped.

A column must be set as unused before it is dropped from a table.

A primary key column cannot be dropped.

Multiple columns can be dropped simultaneously using the ALTER TABLE command.

In Oracle Database 12c, the operations related to dropping columns from a table include several behaviors, each specified clearly in Oracle documentation and best practices:
* B. A column drop is implicitly committed: Dropping a column in Oracle using the ALTER TABLE
… DROP COLUMN command is a DDL (Data Definition Language) operation, which means it cannot be rolled back. DDL commands in Oracle are automatically and implicitly committed, meaning that once a column is dropped, the action is finalized immediately.
* C. A column that is referenced by another column in any other table cannot be dropped: In Oracle, if a column is being referenced by a foreign key constraint or any dependency from another table, you cannot directly drop it until those references are removed or disabled. This ensures data integrity across related tables.
* E. A primary key column cannot be dropped: The primary key constraint is critical for identifying unique rows within a table. Oracle does not allow the dropping of columns that are part of a primary key without first dropping the constraint or modifying it to exclude the column you intend to drop.
References:
* Oracle Database SQL Language Reference 12c, specifically sections discussing DDL operations and constraints.
In Oracle Database 12c, the operations related to dropping columns from a table include several behaviors, each specified clearly in Oracle documentation and best practices:
* B. A column drop is implicitly committed: Dropping a column in Oracle using the ALTER TABLE
… DROP COLUMN command is a DDL (Data Definition Language) operation, which means it cannot be rolled back. DDL commands in Oracle are automatically and implicitly committed, meaning that once a column is dropped, the action is finalized immediately.
* C. A column that is referenced by another column in any other table cannot be dropped: In Oracle, if a column is being referenced by a foreign key constraint or any dependency from another table, you cannot directly drop it until those references are removed or disabled. This ensures data integrity across related tables.
* E. A primary key column cannot be dropped: The primary key constraint is critical for identifying unique rows within a table. Oracle does not allow the dropping of columns that are part of a primary key without first dropping the constraint or modifying it to exclude the column you intend to drop.
References:
* Oracle Database SQL Language Reference 12c, specifically sections discussing DDL operations and constraints.

Q55. Examine the structure of the MEMBERS table: (Choose the best answer.)

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution?

It displays all cities in descending order, within which the last names are further sorted in descending order.

It fails because a column alias cannot be used in the ORDER BY clause.

It fails because a column number and a column alias cannot be used together in the ORDER BY clause.

It displays all cities in ascending order, within which the last names are further sorted in descending order.

Q56. Examine the commands used to create DEPARTMENT_DETAILS and
COURSE_DETAILS tables:
You want to generate a list of all department IDs that do not exist in the COURSE_DETAILS table.
You execute the SQL statement:
What is the outcome?

It fails because the join type used is incorrect.

It executes successfully and displays the required list.

It executes successfully but displays an incorrect list.

It fails because the ON clause condition is not valid.

Q57. Which two statements are true regarding the COUNT function? (Choose two.)

A SELECT statement using the COUNT function with a DISTINCT keyword cannot have a WHERE clause.

COUNT(DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and NULLs in the INV_AMT column.

COUNT(cust_id) returns the number of rows including rows with duplicate customer IDs and NULLs in the CUST_ID column.

COUNT(*) returns the number of rows including duplicate rows and rows containing NULL value in any column.

The COUNT function can be used only for CHAR, VARCHAR2, and NUMBER data types.

Q58. Which two statements are true about dropping views?

Read only views cannot be dropped.

The creator of a view to be dropped must have the drop ANY_ VIEW privilege.

Data selected by a view’s defining query is deleted from Its underlying tables when the view is dropped.

Views referencing a dropped view become Invalid.

CASCADE constraints must be specified when referential integrity constraints on other objects refer to primary or unique keys In the view to be dropped.

Q59. Examine the description of the EMPLOYEES table:

NLS_DATE_FORMAT is set to DD-MON-YY.
Which query requires explicit data type conversion?

SELECT salary + 120.50 FROM employees;

SELECT SUBSTR(join date, 1, 2)- 10 FROM employees;

SELECT join date 11.’11 salary FROM employees;

SELECT join date FROM employees where join date > *10-02-2018*;

SELECT join date + 20 FROM employees;

Q60. Examine this data in the EMPLOYERS table:

Which statement will execute successfully?

SELECT dept_id, MAX (Last_name), SUM (salary) FROM employees GROUP BY dept_id

SELECT dept_id, LENGTH (last_name), SUM (salary) FROM employees GROUP BY dept_id

SELECT dept_id, STDDEV (last_name), SUM (salary) FROM employees GROUP BY dept_id

SELECT dept_id, INSTR (last_name,’A’), SUM (salary) FROM employees GROUP BY dept_id

Q61. Examine the description of the PROMOTIONS TABLE:
You want to display the unique is promotion costs in each promotion category.
Which two queries can be used?

SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;

SELECT promo_cost, promo_category FROM promotions ORDER BY 1

SELECT promo_category, DISTINCT promo_cost FROM promotiong ORDER BY 2:

select DISTINCT promo_categoryIl ‘has’||promol_cost as COSTS FROM promotions ORDER BY 1:

SELECT DISTINCT promo_cost ||’in’IIDISTINCT promo_category promotions ORDER BY1:

Thus, check the Oracle website first, as this vendor offers a full training program that includes more than 17 hours of expert training and credible material, namely:

After more than 15 hours of intensive training with expert Oracle instructors, candidates will be asked to take a short course: Prepare for Oracle Database SQL Certification. Its main purpose is to prepare students in detail for the exam process, including specifics of performance and preparation, as well as information on how to approach questions, take the exam online and get the results. With these short lectures, you’ll have no more questions about the test-writing procedure, allowing you to concentrate fully on your preparation.
Oracle Database 19c: SQL Workshop. The enhanced course curriculum will introduce students to the Oracle Database 19c technology and its features. As you progress through the sections, you will become increasingly immersed in understanding the concepts of relational databases and the powerful SQL programming language. In addition, at the end of the program, students will be given a sound understanding of how to use SQL when working with databases, namely manipulating data in tables, creating database objects, and writing queries to tables. After that, practice classes will not only help you feel confident during the 1Z0-071 exam but also immediately apply the skills of using SQL and the Oracle Database 19c in everyday workflows.

Meanwhile, if you have no time constraints and are serious about your prep process, check out the books and study guides available on the Amazon website.

‘OCA Oracle Database SQL Exam Guide (Exam 1Z0-071) (Oracle Press) 1st Edition’ by Steve O’Hearn, one more reference manual designed both for preparation for the Oracle Database SQL Certified Associate certification and for the daily completion of the tasks related to Oracle Database products. The material covers every topic of the Oracle 1Z0-071 exam, including hierarchical retrieval, regular expression support, and user access control. Moreover, by ordering the book you get not only a bare theory but also detailed explanations, lively examples, and realistic questions. And, along with this guide, you will be given access to two practice exams that are fully aligned with the live exam format. You can purchase its Kindle version or the print edition.
‘Study Guide for 1Z0-071: Oracle Database 12c SQL: Oracle Certification Prep’ by Matthew Morris, written by an author of multiple Oracle Database certification prep guides and an OCE badge holder in Oracle SQL direction. Then an Oracle expert like him can cover all of the exam topics in a concise manner and prepare future administrators for Oracle Database SQL Certified Associate certification. Thus, in this study edition, you will learn everything about applying the SQL language when working with Oracle Database products, from restricting and sorting data to using DDL to manage tables and their relationships. In other words, by ordering this book in the Kindle or Paperback version, you will get a true Oracle Database 12c administrator’s guide of how to use SQL and will gain knowledge both for writing the Oracle 1Z0-071 exam and performing daily tasks.

So, the choice is yours, but in any case, plan your preparation beforehand and check the official sources first to grab the opportunity to save a lot of time and write the final test with flying colors.

Exam Questions for 1z0-071 Updated Versions With Test Engine: https://www.actualcollection.com/1z0-071-exam-questions.html

Thus, check the Oracle website first, as this vendor offers a full training program that includes more than 17 hours of expert training and credible material, namely:

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